How many volume of
(Ar Cu= 64; C= 12; H=1)
ans :
Mol Cu = 19.2 grams : 62 gram/moles = 0.3097 moles
Mol = (2/3) x 0.3097 moles = 0.2064 moles
in it means STP condition so
Volume in STP condition = 0.2064 moles x 22.4 L/moles = 4.62 L
2) In titration of 10 mL with NaOH 0.1 M, we get the concentration of
0.2 M. How many volume of NaOH needed?
ans :
mol = 10 mL x 0.2 mmol/mL = 2 mmol
mol NaOH = 2 x 2 mmol = 4 mmol
so volume NaOH = 4 mmol : 0.1 mmol/mL = 40 mL
3) We can make Hydrogen gas by using this following reaction :
with Ar of Al = 27 g/moles, so How many of grams Al which is needed to form Hydrogen 44.8 L in STP condition?
ans :
Mol Hydrogen = 44.8 L : 22.4 L/moles = 2 moles
Mol Al = (2/3) x 2 moles = 1.333 moles
Grams of Al = 1.333 moles x 27 g/moles = 36 grams
2 comments:
With a pleasure. if any question you can ask me i will help you
Our updates Recent articles:
Post a Comment